function foo(a)
         a=a+1
         b=return(a)
         c=52
endfunction
foo(42);

assert_checkequal(43,b)

the above code is right out of the help file for return: so foo is returning the value of a as b. And the above does work.  However, when I modify the next to last line as follows:

x=foo(42), I'm assigning b into x, at least that's what I thought. Instead I get

Wrong number of output arguments. as an error.  This would have worked in C or C++, so what am I missing here?  Also in the help file there is a mention to the use of the following syntax:

\r\n

\r\n \r\n\r\nHow do I know what gets assigned to x unless there is a return(a). After all there is an a and a c in the function.  And the code doesn't work anyway.  The mention of this form of function declaration is minimal, to say the least, and to further exacerbate the matter the help utility does not show anything when I search for function. I did accidentally find some information on debugging, which saved me from making a post about where the debugger is.