Discrete fourier transform using dft
Title
Question
My scilab version 6. 0.2 is not identifying dft function showing undefined variable while calling it
Scilab Digital-Signal-Processing 03-04 min 0-10 sec
Answers:
Hi,
Please take a look at point no. 9 of the following instruction sheet concerning your query.
'https://spoken-tutorial.org/media/videos/29/Scilab-Instruction-Sheet-English.pdf'
The command dft() has been removed in the latest versions of Scilab. See the help for fft() <a href="https://help.scilab.org/docs/6.1.0/en_US/fft.html" target="" title="">here</a>. See the last example on that page on "Using explicit formula for 1-D discrete Fourier transform".
Rupak
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