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Discrete fourier transform using dft
Title
Question
My scilab version 6. 0.2 is not identifying dft function showing undefined variable while calling it

Scilab Digital-Signal-Processing 03-04 min 0-10 sec 08-05-20, 6:43 p.m. anupama2020

Answers:

Hi,

Please take a look at point no. 9 of the following instruction sheet concerning your query.
'https://spoken-tutorial.org/media/videos/29/Scilab-Instruction-Sheet-English.pdf'


11-05-20, 10:21 a.m. rashpat93


The command dft() has been removed in the latest versions of Scilab. See the help for fft() <a href="https://help.scilab.org/docs/6.1.0/en_US/fft.html" target="" title="">here</a>. See the last example on that page on "Using explicit formula for  1-D discrete Fourier transform".

Rupak

11-05-20, 10:34 a.m. rupakrokade


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