DOUBT IN QUESTION
Title
Question
A)Write a program to check whether the age of the employee is between 20 and 60?
B) Write a program to check whether the age of the employee is between 20 and 59?
Here, I mentioned two questions.Which one is correct?We cant able to write program to the Question A?In the tutorial also asked the students to write coding for A?
B) Write a program to check whether the age of the employee is between 20 and 59?
CODING:-
#include<stdio.h>
int main()
{
int a;
printf("Enter the age of a employee between 20 to 59");
scanf("%d",&a);
if((a/10)==5)
{
printf(" AGE RANGE BETWEEN 50 to 59");
}
else if((a/10)==3)
{
printf(" AGE RANGE BETWEEN 30 to 49");
}
else if((a/10)==2)
{
printf(" AGE RANGE BETWEEN 20 to 29");
}
else
{
printf("AGE NOT IN RANGE\n");
}
return 0;
}
C-and-Cpp Nested-If-And-Switch-Statement 08-09 min 10-20 sec
Answers:
You are missing the case where a/10 is 4
After comparing a/10 to 5, the next else if should check if a/10 is 4
You can do it this way
#include <stdio.h>
int main ()
{
int x;
printf("Type your Age\n");
scanf("%d",&x);
if (x > 60)
{
printf("The age of employee is not between 20-60\n");
}
else if (x < 20)
{
printf("The age of employee is not between 20-60\n");
}
else
{
printf("The age of employee is between 20-60\n");
}
return 0;
}
Hii, I think we can write a code with the help of the information in the video and the pervious video.
I hope the code below might help you or if some one else is having the same doubt. We just have to add the decimal value .2 before %d for the code to read after 6 so that it will read only for the quotient 6.00 and rest which are above that will not be excepted.
#include <stdio.h>
int main()
{
int a;
printf("enter the age between 20 to 60\n");
scanf(".2%d",&a);
//for age less than 20
if(a/10==1)
{
printf("the age is less than the permitted age\n");
}
//for age 20 to 29
else if(a/10==2)
{
printf("the age group is between 20 to 29\n");
}
//for age 30 to 39
else if(a/10==3)
{
printf("the age group is between 30 to 39\n");
}
//for age 40 to 49
else if(a/10==4)
{
printf("the age group is between 40 to 49\n");
}
//for age 50 to 59
else if(a/10==5)
{
printf("the age group is between 50 to 59\n");
}
//for age 60
else if(a/10==6.00)
{
printf("the age group is 60\n");
}
//for age 61 and above
else
{
printf("the age is not in range\n");
}
return 0;
}
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